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> Industry newsScrew pump and bushing physical principles
2017-10-31
When
the rotor moves in the stator bush, the rotational movement of the
rotor in the stator bush is only a plane movement due to the rotational
displacement of the rotor due to the rotation of the sucker rod. Draw the bushing section on the z = 0 plane (the z axis is pointing from the paper). After
the rotor into the bushing, the rotor itself axis o2z from the
centerline of the liner oz distance E, the cross section of the rotor
section of the center of the circle is located in o1, o2 as the center
to o1o2 = E for the radius of the circle, known as the rotor Of
the center of the circle; o as the center of the circle, oo1 = 2E for
the radius of the circle, known as the center of the bushing in Figure
1-10b draw the same rotor - stator sub-arbitrary section z. Obviously,
the elongated shape of the bushing in this section is constant, except
that the long axis OM is related to the size of the angles φ, φ and z of
z = 0, since z = (T / 2π) φ, φ = 2πz / T. Because
the rotor is in the same position (the rotor does not rotate), the
rotor centerline o2 and the moving center circle are unchanged, but in
the section z, the cross section of the rotor is not o1, but the moving
center circle turns from o1 The
angle φ1 is because z = (t / 2π) φ1, so that is to say, from z = 0
cross section to z section, the rotor angle φ1 is equal to twice the
bushing angle φ. In
Figure 1-10b, o o2 points for yo2N = φ1 and the center of the circle to
the point o1 ', o1' point z is the cross section of the rotor in the
center of the circle, with the center, you can make the rotor section
circle. The
following to prove that the o1 'point must be in the OM straight line,
that is, on the long axis of the bushing, in the center of the circle,
o1o1' arc length o1o1 '= E • φ1 set o1 " The
center circle of the intersection, then in the center of the circle
o1o1 "arc length o1o1" = 2Eφ comparison o1o1 'and o1o1 "arc length,
because φ1 = 2φ, then o1o1' = o1o1" This shows that o1 'and o1 " ,
And is located on the long axis of the bushing, so that in any section
z, the center of the cross section of the rotor is located on the long
axis of the bushing, and is the intersection of the moving center circle
and the long axis of the bushing. In
the case of the rotor operation, the center of the rotor section in the
arbitrary section z is reciprocated linearly along the long axis of the
bushing. As shown in Figure 1-11, the velocity of the o1 ' The components are υx, υy, and are synthesized according to the motion described above.